Question

A gun moves backward when a bullet is fired from it a)name the principle behind it b)find the recoil velocity of gun when a bullet of mass 0.2g is fired with a velocity of 300m/s mass of gun is 2kg​

Answer 1

Answer:

a) The principle behind it is the conservation of momentum from the Newton's third law of motion i.e. ''every action has equal and opposite reaction.''

b) Given,  the recoil velocity(v₂) of gun when a bullet of mass 0.2g (m₂) is fired with a velocity of 300m/s(m₁) mass of gun is 2kg ​(m₁) .

         We have the formula , if the initial velocity is 0 from the conservation of momentum : -

=> m₁v₁ = m₂v₂            

=> 2Kg * 300m/s = 0.2 * 10⁻³ Kg * v₂

=> v₂ =  600/(0.2 * 10⁻³) m/s

=> v₂ = 3 * 10⁶ m/s (Ans.) is the recoil velocity .

                                 Hope it helps

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Answer 2

Answer:

it is the third law of Newton i.e every action has equal amount of reaction