A Gun of maas 3kg fires a bullet of mass 30 g the bullet takes 0.003 seconds to move through the barrel of the gun and acquires a velocity of 100m/s .Calculate the force exerted on gunman due to recoil of the gun.
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We know that a = v-u/t
= 100 - 0/0.003
= 100/0.003
= 33333.3333
Force exerted on gunman due to recoil of the gun, F = ma = 3kg * 33333.3333
= 0.03 * 33333.3333
= ~ 1000N
Hope this helps!
= 100 - 0/0.003
= 100/0.003
= 33333.3333
Force exerted on gunman due to recoil of the gun, F = ma = 3kg * 33333.3333
= 0.03 * 33333.3333
= ~ 1000N
Hope this helps!
Rakshita111:
I havee a doubt broo
Whats that
After 3 kg howw did u get 0.03??
hahaha..Conversion
In the question, it is given that mass 3 kg fires a bullet of mass 30g. so 30g = 0.03kg.
Okkk okk thnxxx
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