Question

A Gun of maas 3kg fires a bullet of mass 30 g the bullet takes 0.003 seconds to move through the barrel of the gun and acquires a velocity of 100m/s .Calculate the force exerted on gunman due to recoil of the gun.

Answer 1

We know that a = v-u/t

                           = 100 - 0/0.003

                           = 100/0.003

                            = 33333.3333

Force exerted on gunman due to recoil of the gun, F = ma = 3kg * 33333.3333
                         
                                                                                                =  0.03 * 33333.3333

                                                                                                 = ~ 1000N


Hope this helps!