Question

A gun of mass 10kg fires 4 bullets per second. The mass of each bullet is 20g and the velocity of the bullet when it leaves the gun is 300ms¹. The force required to hold the he gun while firing is

Answer 1

MASS OF THE BULLET=10 KG
AND VELOCITY OF BULLET=300 ms^-1
THEREFORE FORCE ON BULLET=10*4*300
= 12000
FORCE IS DIRECTIONALLY PROPORTIONAL TO RATE OF CHANGE OF MOMENTUM
THEREFOR PER SECOND A BULLET APPLIES A FORCE OF MV
ACCELARATION =V-U/T
U-0
T = 1
THEREFORE A-V
THEREFORE FORCE BY ONE BULLET=MV
= 20*300
= 6000

Answer 2

hey mate.
here's the solution