Physics, asked by Puja6394, 1 year ago

A gun of mass 3 kg fires a bullet of mass 30 g the bullet takes 0.003s to move through the barrel of the gun and accquires a velocity of 100m/s Calculate:- 1)The velocity with which the gun recoils. 2) The force exterted on gunman due to recoil of gun.

Answers

Answered by Atif11111
0
answer of 1 is 0zero yes I'm right
Answered by Anonymous
123

AnsWer:

  • The velocity with which the gun recoil is \sf - 1 \: m/s^{2}

  • The force exerted on gun man due to recoil of the gun is 1000 N.

GIVEN :

  • Mass of gun = 3 kg.
  • Mass of bullet = 30 g.
  • Tune, t = 0.003 sec.
  • Velocity, v = 100 m/s.

TO CALCULATE :

  • The velocity with which the gun recoils.
  • The force exerted by the gun man due to recoil of the gun.

FORMULA :

\sf Force \: = \: \dfrac {\Delta p}{\Delta t}

SOLUTION :

Net force on gun and bullet, system is zero.

\hookrightarrow \sf 3 \: \times \: v \: (30 \times 10^{-3}) \: \times 100 \: = \: 0

\hookrightarrow \sf 3v \: = \: - (30 \: \times \: 10^{-1}

\therefore \boxed{\sf V \: = \: - 1 \: m/s^{2}}

\bold\orange{Force \: = \: \dfrac {\Delta p}{\Delta t}}

\hookrightarrow↪ \sf \dfrac {m(v \: - \: 0)}{0.003}

\hookrightarrow↪ \sf \dfrac {3 \: \times \: 1}{0.003}

\therefore \boxed{\sf F \: = \: 1000 \: N}

hope help u mate ✌

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