A gun of mass 50 kg fires a bullet of mass 0.5 kg with velocity of 200m/s. If the gun moves through 1 m back before coming to rest , the frictional force is
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According to question
Mass of Gun = M = 50 Kg
Mass of bullet = m = 0.5 Kg
Initial velocity of Gun = u = 200 m/ s
Final Velocity = v = 0
Distance S = 1 m
Thus
V^2 + u^2 = 2 * a * S
40000 = 2 * a * 1
Thus
a = 20000 m/s^2
Thus Force = m *a
= 0.5 * 20000
= 10000 N
Mass of Gun = M = 50 Kg
Mass of bullet = m = 0.5 Kg
Initial velocity of Gun = u = 200 m/ s
Final Velocity = v = 0
Distance S = 1 m
Thus
V^2 + u^2 = 2 * a * S
40000 = 2 * a * 1
Thus
a = 20000 m/s^2
Thus Force = m *a
= 0.5 * 20000
= 10000 N
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