Physics, asked by swaraj3184, 6 months ago

A gun of mass M put on a friction less horizontal surface. A bullet of mass m is fired from it, the distance travel by the gun when the distance travelled by the bullet is x......​

Answers

Answered by nisha02345
3

Answer:

Let V and v be the recoiling speed of the gun and velocity of the bullet respectively.

Conserving the momentum, we get

⇒mv−MV=0

⇒V=mv/M

Now conserving the energy, we get

⇒0.5×kd

2

=0.5×MV

2

⇒V

2

=kd

2

/M

⇒(mv/M)

2

=kd

2

/M

⇒v=

m

d

kM

Answered by Anonymous
0

Answer:

Let V and v be the recoiling speed of the gun and velocity of the bullet respectively.

Conserving the momentum, we get

mv-MV=0

V=mv/M

Now conserving the energy, we get

→ 0.5xkd

2

=0.5xMV

Similar questions