A gun of mass M put on a friction less horizontal surface. A bullet of mass m is fired from it, the distance travel by the gun when the distance travelled by the bullet is x......
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Answered by
3
Answer:
Let V and v be the recoiling speed of the gun and velocity of the bullet respectively.
Conserving the momentum, we get
⇒mv−MV=0
⇒V=mv/M
Now conserving the energy, we get
⇒0.5×kd
2
=0.5×MV
2
⇒V
2
=kd
2
/M
⇒(mv/M)
2
=kd
2
/M
⇒v=
m
d
kM
Answered by
0
Answer:
Let V and v be the recoiling speed of the gun and velocity of the bullet respectively.
Conserving the momentum, we get
mv-MV=0
V=mv/M
Now conserving the energy, we get
→ 0.5xkd
2
=0.5xMV
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