Question

a gun throws a shell with a muzzle speed of 98m/s. When the gun is elevated at 45°, the range is observed as 900m. Due to air resistance its range is decreased by​

Answer 1

Answer:

80m

Explanation:

Range in the absence of air resistance =

      R = u×u sin2θ/g

      R = 98×98× sin (2×45)/9.8 = 980 m.

Therefore, decrease in range due to sir resistance = 980−900 = 80m

Answer 2

Air resistance range is, 80m.

Definition of projectile motion.

The motion of an object hurled (projected) into the air is known as projectile motion. After the initial force that propels the object into the air, it is only subjected to the pull of gravity. The object is known as a projectile, and the course it takes is known as a trajectory.

Range in the absence of air resistance.

R = u×u sin2θ/g

 R = 98×98× sin (2×45)/9.8

R = 980 m.

Due to strong resistance, the range has shrunk to 980-900 = 80m.

Hence, The range is reduced by 80 meters due to air resistance.

Learn more about projectile motion here,

https://brainly.in/question/208506?msp_poc_exp=4

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