Question

a gun weighing 4 kg fires a bullet of 40 g with a velocity of 500m/s with what velocity it recoil​

Answer 1

according to momentum conservation,

mass of gun* recoil velocity = mass of bullet* velocity of bullet.

4* V = 40/1000 * 500

V=5 m/s (backwards)

opposite to the direction of bullet firing.

Answer 2

Explanation:

Momentum of gun = Momentum of bullet

mass of gun + recoil velocity of gun = mass of bullet + velocity of bullet

4 × v = 40/1000 × 500

4v = 20

v = 20/4

v = 5

velocity of recoil = 5 m/s

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