Question

A guy wire attached to a vertical pole of height 18 m is 24 m long has a stake attached to the other end. How far from the base of pole should the stake be driven so that the wire will be taut?

Answer 1

SOLUTION :  

Here, the vertical pole makes a right angle with ground, so use Pythagoras Theorem to find the required value.

Let OB be the vertical pole and AB be the wire.  

In ∆AOB,

AB² = OB² + OA²

[ by using pythagoras theorem]

(24)² = (18)² + OA²

576  = 324 + OA²

576  - 324 =  OA²

252 = OA²

OA = √ 252  

OA = √(6 × 6 × 7 )

OA  = 6√7 m

Hence, the distance of the stake from the base of pole is  6√7 m.

HOPE THIS ANSWER WILL HELP YOU

Answer 2

$\huge{\boxed{\sf{Answer}}}$

• A guy wire attached to a vertical pole of height 18 m is 24 m long.
• We have to find : How far from the base of pole should the stake be driven so that the wire will be taut.

Here,

Let, AB be the height of vertical pole.

AC be a wire.

In ΔABC, By using pythagoras theorem we get, :-

( Hypotenuse )² = ( Height )² + ( Base )²

AC² = AB² + CB²

24² = 18² + CB²

576 = 324 + CB²

576 - 324 = CB²

252 = CB²

6√7m  =  CB

HENCE, THE STAKE MAY BE PLACED AT A DISTANCE CB = 6√7m, FROM THE BASE OF THE POLE.