Question

A gymnast with mass 50 kg suspends herself from lower end of a rope. the upper end of rope is attached to the ceiling. what is the tension at the top of the rope?

Answer 1

F=Mg
T=Mg
T=50*10
T=500N
Tension everywhere in the rope must be equal

Answer 2

Answer : The Tension developed at the top of the Rope is 490N Step-by-step Explanation : Given : A gymnast with mass 50 kg suspends herself from lower end of a rope. the upper end of rope is attached to the ceiling. To find : The tension at the top of the rope = ? We know that, Tension will be same throughout the rope. Also, Tension (Force) = Mass × Acceleration due to gravity Substituting the given value in above formula we get, Tension (Force) = 50 × 9.8 -------( since g = 9.8 ) = 490N Hence the Tension developed at the top of the Rope is 490N