A hall has been 15 meters long and 12 meters broad if the sum of the area of the flor and ceiling is eqal to sum of the area of 4 walls the volume of the hard disk
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l =15
b =12
Area of floor =l × b
Area of ceiling =l × b
Area of 4 walls = 2 (l +b ) × h
ATQ
l×b + l×b = 2 (l +b ) × h
2 ×l × b = 2(l +b ) × h
l×b = (l +b ) × h
h = ( l ×b) / (l + b)
=15×12/27
=20/3
Volume =l × b × h
=15 × 12 ×20/3
=1200
_______________________
HOPE , IT HELPS ... ✌️
______________________
______________________
l =15
b =12
Area of floor =l × b
Area of ceiling =l × b
Area of 4 walls = 2 (l +b ) × h
ATQ
l×b + l×b = 2 (l +b ) × h
2 ×l × b = 2(l +b ) × h
l×b = (l +b ) × h
h = ( l ×b) / (l + b)
=15×12/27
=20/3
Volume =l × b × h
=15 × 12 ×20/3
=1200
_______________________
HOPE , IT HELPS ... ✌️
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