Math, asked by adivk, 1 year ago

a hall has dimensions 24*8*6m find the length of the longest pole which can be accommodated in the hall

Answers

Answered by kiki9876
9
Hey mate!

Here is your answer > >

Length of hall=24 m

Breadth of hall=8 m

Height of hall=6 m

Length of longest pole= Diagonal of hall

d^2=l^2+b^2+h^2

d^2=24^2+8^2+6^2

d^2=576+64+36

d^2=676

d^2=26^2

d=26 m

Answer=26 m

Hope it helps!

Thankyou ☆ ☆






adivk: kiki a doubt what does this mean the upper arrow mean
kiki9876: This is the symbol of representing exponent
adivk: means
adivk: had a question if you don't mind the diameter bof a wheel is 984 find the no of revolution in which it will have to cover a distance of 1540
adivk: and a final one
adivk: the diagonal of a square A is (a+b) find the diagonal of a square B with twice the area of A
nickkaushiknick: No of revolution = Distance Covered / circumference of wheel, just cyou can sole it by calculating 1540 / Pi (984) =
Answered by nickkaushiknick
1

Answer:

26 m

Step-by-step explanation:

Length of Longest pole = diagonal of cuboid

                                =\sqrt{length^2 + breadth^2 + height ^2}

                                =\sqrt{24^2 + 8^2 + 6^2}

                                 =\sqrt{576 + 64 + 36}

                                 =\sqrt{676}

                                        = 26

length of longest pole that can be accommodate in the hall is 26m

                                   


adivk: Thanks bro loved it
nickkaushiknick: Pleasure bro, please mark it as brainliest if solution was helpful :)
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