Question

A hall is 10 m by 8 m by 5 m. It has 4 windows measuring 1.5 m x 1 m and two doors of dimension 2 mx 1.5 m. Find the cost of painting the walls and ceiling at 20 per sq m.​

Answer 1

Answer:

Dimensions of wall:

Length = 14 m

Breadth = 10 m

Height = 6.5 m

Dimensions of windows

Length = 1.5 m

Breadth = 1 m

And,Length of doors = 2.5 m

Breadth of doors = 1.2 m

Cost = RS 35 per m

2

Now,

Area of four walls = 2(Length of walls × Height of walls) +2(Breadth of walls × Height of walls)

=2(14×6.5)+2(10×6.5)

=182+130

=312

⇒ Area of four walls is 312m

2

Area of two doors = 2(Length of doors × Breadth of doors)

=2(2.5×1.2)

=6

⇒ Area of two doors is 6m

2

Area of four windows = 4(Length of windows × Breadth of windows)

=4(1.5×1)

=6

⇒ Area of four windows is 6m

2

Therefore,

Area to be painted = Area of 4 walls − (Area of 2 doors + Area of 4 windows)

=312(6+6)

=300

⇒ Area to be painted is 300m

2

Cost of painting =300m

2

× Rs 35 per m

2

=Rs10500

Step-by-step explanation:

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