Question

a hall is 10m long 8m broad.it is to be laid with square tiles of 10cm sides.find the number of tiles required

Answer 1

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Answer 2

The number of tiles required is 8000.

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Let's understand a few concepts:

We will use the following formulas to calculate the required number of tiles:

• $\boxed{\bold{Area \:of\:rectangle = length \times breadth}}$

• $\boxed{\bold{Area\:of\:square = side^2 = a^2}}$

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Let's solve the given problem:

The dimensions of the hall:

Length = 10 m

Breadth = 8 m

∴ The area of the hall = length × breadth = 10 × 8 = 80 m²

The length of each side of each square tile (a) = 10 cm = $\frac{10}{100}\:m = 0.1 \:m$ . . . [∵ 1 cm = $\frac{1}{100}\:m = 0.1\:m$]

∴ The area of each square tile = a² = 0.1² = 0.01 m²

Now,

The required number of tiles to lay along the hall are,

= $\frac{Area \:of\:the\:hall}{Area\:1\:square\:tile}$

= $\frac{80\:m^2}{0.01\:m^2}$

• on multiplying both numerator and denominator by 100

= $\frac{80\times 100}{0.01\times 100}$

= $\frac{8000}{1}$

= $\bold{8000}$

Thus, the number of tiles required is 8000.

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