Question

A hall is 13 meters 53 cm. long and 8 meters 61cm. broad is to be paved with minimum number of square tiles. the number of tiles required is?

Answer 1

Length of the hall = 13m 53cm = 13053m

Width of the hall = 8m 61cm = 8061m

Area of the hall = (13053×8061)m^2

= 105,220,233m^2

Let side be s

ATP

(s)^2 = 105,220,233

s = 10,257.6914

Area of the square tiles = (side)^2

= (10,257.6914×10,257.6914)

= 105,220,233m^2

Number of tiles

= 105,220,233/105,220,233

= 1 tile

Answer 2

Answer:

 Number of tiles =77

Step-by-step explanation:

It is given that a rectangular hall is 13 m 53 cm long and 8 m 61 cm broad which means that rectangular hall is 1353 cm long and 861 cm broad.

The given integers 1353 and 861 can be factorized as follows:

1353=11*123=11*41*3

861=41*3*7

H.C.F of 1353 and 861 is 123.

side of one tile=123

Area of Hall=1353*861=1164933

Area of square tile=15129

There fore

No. of tiles=$\frac{area of hall}{area of square tile}$

                  $=\frac{1164933}{15129} \\\\=77$

So,

     Number of tiles =77

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