Question

A hall is 16 meters long 14 meters broad and 10 meter high. Each wall has a door 5 m. long and 4m. wide and a window of 3m. long and 2m. wide. Find the area of four wall of the room.​

Answer 1

Given:-

• Length of hall = 16m
• Wide of hall = 14m
• Height of hall = 10m

Each wall has a door:-

• Length of wall=5m
• wide of wall=4m

Each windows has :-

• Length of window = 3m
• wide of window = 2m

To Find:-

• Area of four wall=?
• Area of four wall except for wall and window=?

Solution:-

==> Area of four wall= 2(L + B) × H

==> 2(16+14) × 10

==> 2 × 30 × 10

==> 600 m²

==> Area of 4 doors= 4( L × B)

==> 4(5 × 4)

==> 4 × 20

==> 80m²

==> Area of 4 windows= 4(L × B)

==> 4(3 × 2)

==> 4 × 6

==> 24m²

Hence,

==> Area of 4 Wall = 600 m²

==> Area of 4 Wall without door and windows=>

==> Area of 4 Wall - Sum of area of door and window

==> 600 - ( 80 + 24 )

==> 600 - 104

==> 496 m²

Answer 2

Answer:

Given :-

• A hall is 16 meters long, 14 meters broad and 10 meter high.
• Each wall has a door 5 meters long and 4 meters wide and a window of 3 meters long and 2 meters wide.

To Find :-

• What is the area of four wall of the room.
• Area of the rooms except wall and window.

Solution :-

First, we have to find the area of four wall of the room :

Given :

• Length of hall = 16 m
• Breadth of hall = 14 m
• Height = 10 m

As we know that,

$\clubsuit$ Area of four walls of the room of cuboid :

$\longmapsto \sf\boxed{\bold{\pink{Area =\: 2h(l + b)}}}$

where,

• h = Height
• l = Length
• b = Breadth

According to the question by using the formula we get,

$\dashrightarrow$ Area of four walls of the rooms :

$\implies \sf 2 \times 10(16 + 14)$

$\implies \sf 20(30)$

$\implies \sf 20 \times 30$

$\implies \sf\bold{\red{600\: {m}^{2}}}$

Hence, the area of four walls of the room is 600 m² .

$\therefore$ The area of four walls of the room is 600 m².

$\rule{150}{2}$

Again, we have to find the area four windows :

As we know that,

$\clubsuit$ Area of four windows :

$\longmapsto \sf\boxed{\bold{\pink{Area\: =\: 4(l \times b)}}}$

Given :

• Length = 3 m
• Breadth = 2 m

According to the question by using the formula we get,

$\dashrightarrow$ Area of four windows :

$\implies \sf 4(3 \times 2)$

$\implies \sf 4(6)$

$\implies \sf 4 \times 6$

$\implies \sf\bold{\green{ 24\: {m}^{2}}}$

Hence, the area of four windows is 24 m².

Now, we have to find the area of four doors :

$\clubsuit$ Area of four doors :

$\longmapsto \sf\boxed{\bold{\pink{Area =\: 4(l \times b)}}}$

Given :

• Length = 5 m
• Breadth = 4 m

According to the question by using the formula we get,

$\dashrightarrow$ Area of four doors :

$\implies \sf 4(5 \times 4)$

$\implies \sf 4(20)$

$\implies \sf 4 \times 20$

$\implies \sf\bold{\green{80\: {m}^{2}}}$

Atlast, we have to find the area of the rooms except wall and window :

$\bigstar$ Area of the rooms except wall and window = Area of four walls - Area of four doors + Area of four windows

Given :

• Area of four walls = 600 m²
• Area of four doors = 80 m²
• Area of four windows = 24 m²

According to the question by using the formula we get,

$\dashrightarrow$ Area of the rooms except wall and window :

$\implies \sf 600\: m^2 - 80\: m^2 + 24\: m^2$

$\implies \sf 600\: m^2 - 104\: m^2$

$\implies \sf\bold{\red{496\: m^2}}$

$\therefore$ The area of the rooms except wall and window is 496 m².

$\rule{150}{2}$