Question

A hall with length 48 m and breadth 12 m require 64 square -shaped tiles. what will be the perimeter of each tile?​

Answer 1

Perimeter of each tile=12m

Step-by-step explanation:

Given,Length of tile=48m,

Breadth of tile=12m

Number of tiles =64

$Area of Hall=Length \times Breadth$

                            =$48m\times 12m$

 Now$Area \ of\ 1\ square\ tile\times Number\ of\ tiles$=Area of Hall

        $Area\ of\ 1\ tile\times 64$=$48m\times 12m$

        Ares of 1 square tiles = $\frac{48m\times 12m}{64}$

        Area of 1 square tiles=9m

        Area of 1 square tile=$3m\times 3m$

       $Side \times Side$=$3m\times 3m$

      Side= 3m

Now, Perimeter of Square =$4\times Side$

                                           =$4\times Side$

         Perimeter of Square tile =12m

Hence,Perimeter of each tile=12m.

         

Answer 2

Answer:

Perimeter of each tile=12m

Step-by-step explanation:

Given,Length of tile=48m,

Breadth of tile=12m

Number of tiles =64

Area of Hall=Length \times BreadthAreaofHall=Length×Breadth

=48m\times 12m48m×12m

NowArea \ of\ 1\ square\ tile\times Number\ of\ tilesArea of 1 square tile×Number of tiles =Area of Hall

Area\ of\ 1\ tile\times 64Area of 1 tile×64 =48m\times 12m48m×12m

Ares of 1 square tiles = \frac{48m\times 12m}{64}

64

48m×12m

Area of 1 square tiles=9m

Area of 1 square tile=3m\times 3m3m×3m

Side \times SideSide×Side =3m\times 3m3m×3m

Side= 3m

Now, Perimeter of Square =4\times Side4×Side

=4\times Side4×Side

Perimeter of Square tile =12m

Hence,Perimeter of each tile=12m

Step-by-step explanation:

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