A hall with length 48m with breath 12m requires 64 square shaped tiles what will be perimeter of each tile
Answers
Step-by-step explanation:
Given :-
A hall with length 48m with breath 12m requires 64 square shaped tiles.
To find :-
What will be perimeter of each tile ?
Solution :-
Given that
The length of the hall (l) = 48 m
The breadth of the hall (b) = 12 m
We know that
Area of a rectangle = lb sq.units
Area of the given hall = 48×12 sq.m
=> Area = 576 sq.m ----------(1)
Given that
The number of tiles fitted in the hall = 64 square shaped tiles
Area of the hall = area of the 64 square shaped tiles
We know that
Area of a square whose side is a units
= a² sq.units
Area of 64 square shaped tiles
= 64×a² sq.m ---------(2)
From (1)&(2)
=> 64×a² = 576
=> a² = 576/64
=> a² = 9
=> a =±√9
=> a = ±3
Since the side cannot be negative.
=> a = 3 m
Side of the square shaped tile = 3 m
We know that
Perimeter of a square whose side is a units
= 4a units
Perimeter of the each tile = 4×3 m
= 12 m
Answer:-
Perimeter of the each tile is 12 m
Used formulae:-
→ Area of a rectangle = lb sq.units
- l = length
- b = breadth
→ Area of a square whose side is a units
= a² sq.units
→ Perimeter of a square whose side is a units
= 4a units