A hammar of mass 1 kg falls freely frpm a height of 2m. claculate the kinrtic energy and the velocity of hammar just before touching the touching the ground
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u = 0m/s , s = 2m , g = 10m/s^2
v^2=u^2+2gh
v = root 40
Nown, K.E. of hammer :- 1/2mv^2
= 1/2 × 1 × 40 = 20J
v^2=u^2+2gh
v = root 40
Nown, K.E. of hammer :- 1/2mv^2
= 1/2 × 1 × 40 = 20J
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