Question

A hammer of mass 0.5 kg moving at 50 ms-¹ , hits a nail. The nail stops the hammer in a very short time of 0.02 seconds. Calculate the force of the nail on the hammer .​

Answer 1

Force = –1250N

Explanation:

Given:

• Mass of hammer is 0.5 kg.
• Velocity is 50 ms-¹.
• Time is 0.02 seconds.

To Find:

• Force of the nail on the hammer

Formula to be used:

• F = mass × acceleration

Solution: Here we have

• m = 0.5
• t = 0.02
• v = 50 ms-¹
• u = 0

As we know that

Acceleration = (v – u/t)

Now put the values on formula

$\implies{\rm }$ F = ma

$\implies{\rm }$ m(v – u/t)

$\implies{\rm }$ 0.5(0 – 50/0.02)

$\implies{\rm }$ 0.5 (–50/0.02)

$\implies{\rm }$ 0.5 × –2500

$\implies{\rm }$ –1250N

Hence the force of the nail on the hammer is –1250 N.

Answer 2

✍ Given :-

• Mass Of Hammer = 0.5kg

• Initial Velocity = 0m/s.

• Final Velocity = 50m/s

• Time = 0.02 seconds.

✍ To Find :-

• Force of the nail.

✍ Solution :-

We know that,

Force = Mass × Acceleration.

Now, Acceleration :- (v - u)/t.

So, Equation :-

F = m(v - u)/t.

Put the values.

➛F = 0.5(0-50)/0.02

➛F = 0.5 × -50/0.02

➛F = 0.5 × -2500.

➛F = -1250.

✔ Hence, Force of the nail on hammer is -1250 Newton.