Question

a hammer of mass 1 kg falls freely from a height of 2 m. calculate (1) the velocity of hammer (2) the kinetic energy of the hammer just before it touches the ground.​

Answer 1

Answer:

no velocity does not depend on mass of body .

Explanation:

velocity=√2gh

=√2*10*2

=2√10 m/s

ke=1/2 m v*v

=1/2*1*40

=20 joules

no velocity does not depend on mass of body .

Answer 2

Answer:

1.velocity of hammer v= 6.26 m/s

2.kinetic energy E =19.59 J

Explanation:

Note: √ this is the sign of root ok

jidhar maine square likha h uska matlab h mv ke upar 2 ok

It is given that,

Mass of the hammer m=1 kg

Height h= 2 m

1 Let v is the velocity of hammer It can be calculated usin conservation of energy as :

v=√2 gh

v= √2×9.8×2

v= 6.26 m/s

2. Let is the kinetic energy of the hammer jist before it touches the ground.It is given by:

E = 1/2 mv square

E =1/2×1×(6.26) square

E= 19.59 J

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