Question

a hammer of mass 1kg strikes on the head of a nail with a velocity of 2 ms inverse it drives the nail 0.01 m into a wooden block find the force applied by the hammer and the time of impact

Answer 1

Let the force applied on the nail = F

displacement of nail (s)= 0.01m

here, all the kinetic energy of the hammer is used to do the work.

So work done = KE of hammer

=> Fs= 1/2 mv^2

=> F × 0.01 = 1/2 × 1 × 2^2

=> 0.01F = 2

=> F = 2/0.01 = 200N

So force is 200N.
__________________________

We know that force = rate of change of momentum of hammer

=> 200 = mv/t
(where t is time of impact)

=> 200 = 1×2/t

=> t = 2/200

=> t = 0.01 second

time of impact = 0.01 sec

Answer 2

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Let the force applied on the nail = F

displacement of nail (s)= 0.01m

here, all the kinetic energy of the hammer is used to do the work.

So work done = KE of hammer

=> Fs= 1/2 mv^2

=> F × 0.01 = 1/2 × 1 × 2^2

=> 0.01F = 2

=> F = 2/0.01 = 200N

So force is 200N.

__________________________

We know that force = rate of change of momentum of hammer

=> 200 = mv/t

(where t is time of impact)

=> 200 = 1×2/t

=> t = 2/200

=> t = 0.01 second

time of impact = 0.01 sec

HOPE SO IT WILL HELP....