One of the exterior angles of a triangle is 100° nd the interior opposite angles are in the ratio 2:3.find the angle of a triangle
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4
Let the interior opposite angles be 2x and 3x
2x+3x=100
5x=100
x=100/5
x=20
2x=2(20)=40
3x=3(20)=60
2x+3x=100
5x=100
x=100/5
x=20
2x=2(20)=40
3x=3(20)=60
Answered by
6
Let the common ratio be x.
Then, interior opposite angles=2 x and 3 x
Exterior angle =100°
Using exterior angle property that states that the sum of interior opposite angles gives the value of exterior angle
So,
exterior angle = sum of interior opposite angles
100°=2x+3x
100°=5x
100°/5=x
20°=x
So, interior opposite angles are
2x =2×20°
= 40°
and 3× 20°=60°
angle remaining + exterior angle = 180° (Linear pair)
let the angle remaining be y.
y+100°=180°
y=180°-100°
y=80°
Then, interior opposite angles=2 x and 3 x
Exterior angle =100°
Using exterior angle property that states that the sum of interior opposite angles gives the value of exterior angle
So,
exterior angle = sum of interior opposite angles
100°=2x+3x
100°=5x
100°/5=x
20°=x
So, interior opposite angles are
2x =2×20°
= 40°
and 3× 20°=60°
angle remaining + exterior angle = 180° (Linear pair)
let the angle remaining be y.
y+100°=180°
y=180°-100°
y=80°
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