Question

A hammer of mass 400g, moving at 30ms⁻¹, strikes a nail. The nail stops the hammer in a very short time of 0.01s. What is the force of the nail on the hammer? (Ans:1200 N)

Answer 1

Initial Velocity (u) = 0

Final Velocity (v) = 30 m/s.

Time taken = 0.01 seconds.

∴ Acceleration (a) = (v - u)/t

∴ a = (30 - 0)/0.01

⇒ a = 30/0.01

∴ a = 3000 m/s².

Mass of the Hammer = 400 g.

= 0.4 kg.

Now, Using the Second law of the motion,

Force = mass × acceleration.

∴ Force = 0.4 × 3000

⇒ F = 1200 N.

Hence, the Force acting on the nail is 1200 N.

Hope it helps.

Answer 2

heya...

Here is your answer...

Given;

Finial velocity = 30 m/s^-1

Time taken = 0.01 seconds

Initial velocity = 0

Acceleration = V-u/t

= 30-0/0.01

= 30/0.01

= 3000 m/s^2

Force = Mass × acceleration

= 0.4 × 3000

= 1200 N

It may help you....☺☺