Question

a hammer of mass 500g, moving 50m/s strike a nail. The nail stops the hammer in a time of 0.01s what is force of the nail on the hammer?

Answer 1

Answer:

mass= 500/1000

= 0.5kg

acceleration = 50/0.01

=5000m/s^2

force = ma

= 0.5× 5000

= 2500Newton

Answer 2

Answer:

-2500N

Explanation:

m=500g=  =0.5kg

v=0

u=50m/s

t=0.01s

f= $\frac{m(v-u)}{t}$

f= $\frac{0.5(0-50)}{0.01}$

f= -2500N or -2500kg$m/s^{2}$