10a+2b=4, 15a-5b=-2 solve by long firm of simultaneous equation method
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Answer:a=1/5
b=1
Step-by-step explanation:let 10a+2b=4......(1)
15a-5b=-2......(2)
multiple 5 by (1) & 2 by (2)
:(10a+2b=4)5=50a+10b=20.........(3)
(15a-5b=-2)2=30a-10b=-4.....(4)
Add (3) & (4)
(50a+10b=20)+(30a-10b=-4)
We get
80a=16
a=16/80
a=1/5
put the value of a in (1)
10×1/5+2b=4
2+2b=4
2b=4-2
b=2/2=1
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