A hammer of mass 500gm moving in 50ms strike the hammer in a very short time of 0.01 sec .What is the force on nail in the hammer
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Answered by
1
Answer:
The force of nail on the hammer
F=
Change in momentum of hammer/time
F=
m(v−u)/t=
0.5(0−50)/0.01
=−2500N
Negative sign denotes that the force of nail on the hammer is acting in the direction opposite to that of motion of hammer.
Answered by
1
Answer:
The force of nail on the hammer
F=
Time
Change in momentum of hammer
F= tm(v−u)
= 0.01 ×0.5(0−50)
=−2500N
Negative sign denotes that the force of nail on the hammer is acting
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