Question

A hammer of mass 500gm moving in 50ms strike the hammer in a very short time of 0.01 sec .What is the force on nail in the hammer​

Answer 1

Answer:

The force of nail on the hammer

F=

Change in momentum of hammer/time

F=

m(v−u)/t=

0.5(0−50)/0.01

=−2500N

Negative sign denotes that the force of nail on the hammer is acting in the direction opposite to that of motion of hammer.

Answer 2

Answer:

The force of nail on the hammer

F=

Time

Change in momentum of hammer

F= tm(v−u)

= 0.01 ×0.5(0−50)

=−2500N

Negative sign denotes that the force of nail on the hammer is acting