Question

a hammer of mass 500kg moving at 50m/s strikes a nail the nail stops the hammer in a very short time of 0.01 sec what is the force of the nail on hammer

Answer 1

hey mate this much is needed
hope it may help u

Answer 2

$\boxed{\begin{minipage}{11 cm} According to the Question \\ \\ \ m = 500kg(Mass\;of\;hammer) \\ \\ u = 50m/s(Initial\;velocity\;of\;hammer \\ \\ v = 0m/s(Final\;velocity\;of\;hammer) \\ \\ t=0.01s(Time\;taken\;by\;hammer\;to stop \end{minipage}}$

★Force exerted by nail = F

$\tt{\rightarrow F=\dfrac{m(v-u)}{t}}$

$\tt{\rightarrow F=\dfrac{500(0-50)}{0.01s}}$

$\tt{\rightarrow F=\dfrac{500\times50\times100}{0.01\times100}}$

$\tt{\rightarrow F=\dfrac{2500000}{1}}$

= 2500000 × m/s²

= 2500000 N

★The nail exerted by force is 2500000 N.

$\boxed{\begin{minipage}{11 cm} Additional Information \\ \\ \ Final\;Velocity=Initial\; velocity+Acceleration\times Time \\ \\ Momentum = Mass\times Velocity \\ \\ Force=Mass\times Acceleration \\ \\ Force = \dfrac{Change\;in\;Momentum}{Time\;Interval} \\ \\ Impulse = Force\times Time \end{minipage}}$