In fig if ab parallel to de angle bac is equal to 35 and angle cde is equal to 53 find angle dce
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Hello mate ☺
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Solution:
It is given that AB∥DE. Therefore, ∠BAC=∠DEC (Alternate Interior Angles)
∠BAC=35° (Given)
Therefore, ∠DEC=35°
In ∆DCE, we have
∠DEC+∠CDE+∠DCE=180° (Sum of three angles of a triangle =180°)
⇒35°+53°+∠DCE=180°
⇒∠DCE=180°−35°−53°=92°
I hope, this will help you.☺
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