Question

a hammer of mass is 400grams,moving at 30's,strikes a nail. the nail stops the hammer in a very short time of 0.01seconds.what is the force of the nail on the hammer?

Answer 1

solution



Here, m = 400 g = 0.4 kg,
u1 = 40 ms–1,
u2 = 0,
t = 0.01 s
The force of nail on the hammer,
F = Change in momentum time
F = m(v - u) / t
= 0.4 (0-40)/0.01

= –1600 N

The negative sign means that the force of nail on the hammer is acting in the direction opposite to that of hammer.

Answer 2

Explanation:

I think it is helpful to you