find this equation z^2-(x-y) =32
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z²-x+y=32
z²-(x+y/z)z-32=0
here a=1, b=x+y/z ,c=-32
z=-(x+y/z)±√ x+y/z ²- 4 (1)(-32)/2(1)
=-(x+y/z)±√x²+y²+2xy/z²+128/2
hope helped !
z²-(x+y/z)z-32=0
here a=1, b=x+y/z ,c=-32
z=-(x+y/z)±√ x+y/z ²- 4 (1)(-32)/2(1)
=-(x+y/z)±√x²+y²+2xy/z²+128/2
hope helped !
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