a hammer of masss 500 g moving at 50 ms strikes a nail the nail stops the hammer in a very short time of 0.01 s what is the force of the nail on the hammer
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Change in momentum = impulse
mv = Ft
0.5×50= f×0.01
F=2500N
mv = Ft
0.5×50= f×0.01
F=2500N
Answered by
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Answer:
mass of the hammer(m)=500g=500/1000kg=0.5kg
velocity=50ms¹
time=0.01s
acceleration=v-u/t=0-50/0.01=-5000ms¹
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