a hammer of nail 500 gram moving at 40 second strikes a nail the nail stop the hammer in a very short time of 0.001 second what is the force of the nail on the hammer???
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Mass of the hammer (m) = 500 g = 0.5 kg
The initial velocity of the hammer (u) = 50 m/s
Time is taken by the nail to the stop the hammer (t) = 0.01 s
The velocity of the hammer (v) = 0 (since the hammer finally comes to rest)
From Newton’s second law of motion
f = m (v – u) / t
Where f = force
f = 0.5 × (0 – 50) / 0.01
f = -2500 N
-ve sign indicates the force of nail on the hammer moving in the opposite direction to that of hammer movement.
Explanation:
OHK MAI DP PE LGATA HU BS 2 MIN KE LIYE
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