A hard nut can be broken by applying a direct force of 5 Newton the same nut is placed in a nutcracker at a distance of 3 cm from the fulcrum if the length of the nutcracker handle is 20 cm what is the minimum effort to break the nut... Please give complete explanation
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Load = 5 N
Load arm = 3 cm
Effort = ?
Effort arm =20 cm
∴ Load x load arm = Effort x Effort arm
3 × 5 = effort × 20
effort = 3 × 5 / 20 = 3/4 N
Thus, to crack the nut the force of 3/4N must be applied at the end of the handle.
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