Question

A hard nut can be broken by applying a direct force of 5 Newton the same nut is placed in a nutcracker at a distance of 3 cm from the fulcrum if the length of the nutcracker handle is 20 cm what is the minimum effort to break the nut... Please give complete explanation​

Answer 1

Load = 5 N  

Load arm = 3 cm  

Effort = ?

Effort arm =20  cm  

 

∴ Load x load arm = Effort x Effort arm  

3 × 5 = effort × 20

effort = 3 × 5 / 20 = 3/4 N

 

Thus, to crack the nut the force of 3/4N must be applied at the end of the handle.

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