Math, asked by Kalai5667, 1 year ago

A hawker sells 4 Oranges in Rs.15. Wahab has to buy 20 Oranges. So he has to spent how much rupees ?

Answers

Answered by psjain

0

for 4 oranges hawker charges 15

therefore for 1 will be 15/4

for 20oranges Wahab has to spent 15/4*20=rs 75

Previous Question

Next Question

Similar questions

Math, 7 months ago

35. Let U = {xe N:15 x 10be the universal set. N being the set of natural numbers. If A = {1, 2, 3, 4} and B = {2, 3, 6, 10}, then wb is the complement of (A - B)? 2012 (a) (6, 10) (b) {1,4} (c) (2, 3, 5, 6, 7, 8, 9, 10; (d) {5, 6, 7, 8, 9, 10}...

Physics, 7 months ago

Light propagates faster through a Medium A than through another Medium B. (a) Which of the two media has a higher optical density? (b) State the condition under which no change in the direction of propagation of a light ray would take place when it passes from Medium A to Medium B.

English, 7 months ago

H Insert the wherever required in these sentences. Put a cross where the is not required. 1. Polo was played by aristocrats in past. 2. Are you fond of nature sports? 3. In pithoo pebbles are piled one on top of other and then hit with a ball. 4. Shashi has retired from test cricket. 5. Wrestling competitions or dangals are held in small towns and villages every year. 6. Chess spread from Persia...

Science, 1 year ago

Is transfer of heat possible between two objects that are not in contact having different temperature? How?

Science, 1 year ago

Classify the following seeds into monocot seed and dicot seed :Wheat, Green gram, Maize, Turkish gram, Bengal gram, Sesame seeds (Til), Pearl millet (Bajra), Rice, Groundnut, Fennel...

Math, 1 year ago

In a triangle ABC AD is perpendicular to BC, prove that AB^2+CD^2=AC^2+BD^2...

Math, 1 year ago

a room is 14 feet long 12 feet broad and 10 feet height find the cost of colouring its wall floor and ceiling with black colour to make it a complete Haunted House give that cost per square feet is rupees 10...

Math, 1 year ago

Evaluate: (2sin 68/cos22)- (2cot15/5tan75)-( 3tan 45* tan 20* tan 40* tan 50 *tan 70*cos 22* 5tan 75/ 5)...