Question

a healthy person eats the following diet -5 gram raw sugar, 4 gram albumin, 10 gram pure buffalo ghee adulterated with 2 gram vegetable ghee( hydrogenated vegetable oil) and 5 gram lignin. How many calories he is likely to get? ​

Answer 1

5×4.0= 20 kcal

4×4.0= 16 kcal

(10+2)=12×9.0= 108kcal

Ans. 144 Kcal

Answer 2

Answer:

144.8cal

Explanation:

The amount of calorie intake of the person depends on the calorific value of the food he is in taking.

The calorific value of a food is the calorie it gives per gram of its intake.

• Carbohydrates have a calorific value of 4.0cal/g
• Fats have a calorific value of 9cal/g.
• Proteins have a calorific value of 4.2cal/g.

So according to this:

5g sugar (carbohydrate) $\times 4=20 \mathrm{cal}$

4g albumin (protein) $\times 4.2=16.8 \mathrm{cal}$

10 + 2g oil (fats) $\times 9=108$

Lignin is not digested in our body, so have no calorific value.

So, total calorie comes out as 144.8cal.