A heap of oranges can be arranged in groups of 10,15,20 with 2 oranges left over .find the least number of oranges in the heap
Answers
The least number of oranges in the heap with 2 oranges left over is 62.
Step-by-step explanation:
Consider the provided information.
A heap of oranges can be arranged in groups of 10, 15, 20 with 2 oranges left over .
First find the LCM of 10, 15 and 20.
10 = 2×5
15 = 3×5
20 = 2×2×5
The LCM is = 2×2×3×5=60
That means the least number of oranges in the heap with no oranges left is 60.
It is given that 2 oranges left over, So add 2 in 60.
60+2=62
Hence, the least number of oranges in the heap with 2 oranges left over is 62.
#Learn more
Find LCM of 92 and 510.Also find their HCF by using LCM.
https://brainly.in/question/858954
Answer:
The Least number of oranges in the heap with 2 oranges left over is 62
Step-by-step explanation:
First find the LCM of 10,15,20
The LCM=60
Therefore, it means in the least number of oranges in the heap with no oranges left over is 60
It is already given that 2 oranges are left over
So ADD 60+2=62
hence , the answer is 62