Question

Simplify 2 root 48 - root 75 - 1 upon root 3. Std 9th SSC board Maths-I (Algebra) Lesson No. 2 Problem Set Q. No. 7 5th sum​

Answer 1

$2 \sqrt{48} - \sqrt{75} - \frac{1}{3} = 2 \sqrt{16 \times 3} - \sqrt{25 \times 3} - \frac{1}{3}$
$= 2 \times 4 \sqrt{3} - 5 \sqrt{3} - \frac{1}{3 } \\ = 8 \sqrt{3} - 5 \sqrt{3} - \frac{1}{3} \\ = 3 \sqrt{3} - \frac{1}{3} \\ = \frac{9 \sqrt{3} - 1 }{3} \\ =$
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Answer 2

Answer:

Step-by-step explanation:

2 \sqrt{48} - \sqrt{75} - \frac{1}{3} = 2 \sqrt{16 \times 3} - \sqrt{25 \times 3} - \frac{1}{3}

= 2 \times 4 \sqrt{3} - 5 \sqrt{3} - \frac{1}{3 } \\ = 8 \sqrt{3} - 5 \sqrt{3} - \frac{1}{3} \\ = 3 \sqrt{3} - \frac{1}{3} \\ = \frac{9 \sqrt{3} - 1 }{3} \\ =