a heap of wheat is in the form of a cone whose diameter is 21 m
and height is 6 metre find its volume the heat is to be covered by Canvas to protect from rain but the rain of the Canvas required
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we know volume of cone is πr.rh/3
=22/7(21/2)(21/2)(6/3)
=(3.14)(21/2)(21/2)(2)
=692.37 sq.m
we know lateral surface area of cone is =πr√(h.h+r.r)
=22/7(21/2)√(6.6+21/2.21/2)
=3.14(10.5)(√(36+110.25)
=33√146.26
=33(12.09)
=399.08 sq.m
the canvas cover required is 399.08 sq.m
=22/7(21/2)(21/2)(6/3)
=(3.14)(21/2)(21/2)(2)
=692.37 sq.m
we know lateral surface area of cone is =πr√(h.h+r.r)
=22/7(21/2)√(6.6+21/2.21/2)
=3.14(10.5)(√(36+110.25)
=33√146.26
=33(12.09)
=399.08 sq.m
the canvas cover required is 399.08 sq.m
vanshsharma21:
sorry wrong ans.
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