A heap of wheat is in the form of a cone with diameter 10.5m and height 7m. Find the area of the canvas required, also find volume
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Diameter = 10.5m
Radius = 5.25m
Height = 7m
(L)² = (7)²+(5.25)²= 49+27.56=76.84
L = ✓76.84= 8.76m
Volume of Heap = 1/3πr²h
= 1/3×22/7×5.25×5.25×7= 607.18/7 = 86.74m³
Canvas required= CSA of heap = πrL
Radius = 5.25m
Height = 7m
(L)² = (7)²+(5.25)²= 49+27.56=76.84
L = ✓76.84= 8.76m
Volume of Heap = 1/3πr²h
= 1/3×22/7×5.25×5.25×7= 607.18/7 = 86.74m³
Canvas required= CSA of heap = πrL
sangeetadahiya75:
Thnx a lot
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