a heap of wheat is the form of a cone of diameter 16.8 M and height 3.5 M find its volume how much cloth is required to just cover the heap?
Answers
Answered by
6
Given h = 3.5m, d = 16.8 Then the radius will be r = d/2 = 8.4m.
We know that volume = 1/3pir^2h
= 1/3 * 22/7 * (8.4)^2 * 3.5
= 5433.12/21
= 258.7 m^3.
We know that Height l = root r^2 + h^2
= root (8.4)^2 + (3.5)^2
= root 82.81
= 9.1m.
Cloth required to just cover the heap = pirl
= 22/7 * 8.4 * 9.1
= 240.24m^2.
We know that volume = 1/3pir^2h
= 1/3 * 22/7 * (8.4)^2 * 3.5
= 5433.12/21
= 258.7 m^3.
We know that Height l = root r^2 + h^2
= root (8.4)^2 + (3.5)^2
= root 82.81
= 9.1m.
Cloth required to just cover the heap = pirl
= 22/7 * 8.4 * 9.1
= 240.24m^2.
Answered by
4
l^2 = 3.5^2 + 8.4^2
l^2 = 82.81
l = 9.1 m
Volume = 1/3 πr^2h
= 1/3 x 8.4 x 8.4 x 3.5
= 82.32 m^3
CSA
= Cloth Required
= πrl
= 22/7 x 8.4 x 9.1
= 240.24 m^2
l^2 = 82.81
l = 9.1 m
Volume = 1/3 πr^2h
= 1/3 x 8.4 x 8.4 x 3.5
= 82.32 m^3
CSA
= Cloth Required
= πrl
= 22/7 x 8.4 x 9.1
= 240.24 m^2
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