Question

A heat engine absorbs 460 J of thermal energy and preforms 10.1 J of work in each cycle. Find the efficiency of the engine

Answer 1

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$\underline{\underline{\huge{\textbf{Solution:}}}}$

Heat absorbed by the Heat Engine $Q_{h} = 460\: J$

Work done by the Heat Engine $W = 10.1\: J$

Efficiency of the Heat Engine is the ratio of work done to heat absorbed.

$\eta = \dfrac{W}{Q_{h}}$

Substituting Values

$\implies \eta = \dfrac{10.1\: J}{460\: J}$

$\implies \eta = 0.0219$

$\implies \eta\% = 2.19\%$

$\therefore$
Efficiency of the Heat Engine = $\underline{2.19 \%}$

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