Question

A heat engine operating between 227 deg c and 27 deg c absorbs 1 kcal of heat from the 227 deg c reservoir per cycle. Calculate (1) the amount of heat discharged into the low temperature reservoir. (2) the amount of work done per cycle. (3) the efficiency of cycle.

Answer 1

Answer:

Calculation of work done:

T

′

=227+273=500 K

T=27+273=300 K

q

′

=1 1 kcal

q

′

w

=

T

′

T

′

−T

w=q(

T

′

T

′

−T

)

Putting the various values in the above reaction

w=1(

500

500−300

)=1×

500

200

=0.4 kcal.

Calculation of heat discharged q

q

′

−q=w

1−q=0.4

q=0.6 kcal