find the area enclosed by a parabola y2=x and the line y +x=2 and the x axis
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Solution
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To get the point of intersection, we have to solve the equation of line
Y+
x=
2
and parabola
y 2
x
.
On solving them we find the coordinates of points of intersection as (4,−2) and (1,1). Drawing perpendiculars from these points on y-axis, we obtain the coordinate as (0,1) and (0,−2).
Thus, required area
=
∫
−2
1
(2−
y−
y 2
[2y−
2
y 2
−
3
y 3
] 1−
−2
= (2−
2
1
−
3
1
)− (
4
−
−
2
4
+
8
3
)
= 2−
6
5
+ 6−
3
8
= 8−
6
21
=
6
27
=
2
9
sq.units
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