Question

a heat pump is use to maintain the
houses at 24 degree c. the house is loosing the heat at the rate of 1800kj/min to the surrounding.the heat pump is driven by an electric motor of power rating 12 kw .find
1 . amount of heat absorbed from surrounding.
2. cop of the heat pump​

Answer 1

Answer:

a heat pump is use to maintain the

houses at 24 degree c. the house is loosing the heat at the rate of 1800kj/min to the surrounding.the heat pump is driven by an electric motor of power rating 12 kw .find

1 . amount of heat absorbed from surrounding.

2. cop of the heat pump

Answer 2

Answer:

a) heat absorbed from surrounding = 18kW

b) cop= 1.66

Explanation:

a] Power rating of heat pump = heat used by heat pump = 12 kW = Q2

Heat absorbed by the surrounding = 1800kJ/min = 1800kJ/60 sec = 30kJ/s = 30kW

Now, we know that to maintain the temperature of a house, incoming heat should be equal to outgoing heat. i.e. $Q_1=30kW$

Also, $Q_1=Q_2+H$

30 = 12 + H

H= 30-12

H=18kW

Hence, the amount of heat absorbed from surroundings = 18kW.

b] coefficient of performance of heat pump is given by,

$\eta = \frac{Q_1}{Q_1-Q_2}$

$\implies \eta = \frac{30}{30-12}$

$\implies \eta = 1.66$

Hence, c.o.p. = 1.66

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