Question

A heater is connected to 240 V and draws a current of 3.5 A. Determine heat dissipated in 15 minutes.​

Answer 1

answer of your choice

Answer 2

The heat dissipated in 15 minutes is 756 kJ.

Explanation:

It is given that,

Voltage, V = 240 V

Current, I = 3.5 A

Let Q is the heat dissipated in 15 minutes or 900 seconds. We know that due to flowing current, some amount of heat is dissipated. It is given by :

$Q=I^2Rt$

or

$Q=VIt$

$Q=240\times 3.5\times 900$

Q = 756000 J

or

Q = 756 kJ

So, the heat dissipated in 15 minutes is 756 kJ. Hence, this is the required solution.

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