Question

A heating appliance working at 230v 460 ohm resistance. what will be the heat generated by 10 minutes ?​

Answer 1

A heating appliance working at 230 V ,  460 Ω resistance ,

We need to find the heat generated in 10 min .

Formula Applied :

$\sf H=I^2Rt\\\\\to \sf H=\left(\dfrac{V}{R}\right)^2Rt\\\\\to \sf \pink{H=\dfrac{V^2t}{R}}\ \; \bigstar$

where ,

• H denotes heat generated
• V denotes potential difference
• t denotes time
• R denotes resistance

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Given ,

• V = 230 V
• R = 460 Ω
• t = 10 min = 600 s

Apply formula ,

$\to \sf H=\dfrac{V^2t}{R}\\\\\to \sf H=\dfrac{(230)^2\times 600}{460}\\\\\to \sf H=\dfrac{230\times 230\times 600}{460}\\\\\to \sf H=230\times 300\\\\\leadsto \sf \orange{H=69,000\ J}\ \; \bigstar$

So , Heat generated in 10 min is 69,000 J .

Answer 2

Answer :-

A heating appliance works at 230 V and 460 Ω resistance. What will be the heat generated by the appliance in 10 minutes?

= Here,

• Potential difference (V) = 230 V
• Resistance (R) = 460 Ω
• Time (t) => 10 minutes = 600 seconds.

By using Ohm's law,

=> V = IR

=> I = V/R

=> I = 230/460 A

=> I = 1/2 A

=> I = 0.5 A

Hence, the strength of the current is 0.5 Ampere.

Now, From Joule's law of heating effect of current,

=> H = I²Rt

=> H = (0.5)² × 460 × 600

=> H = 69000 Joules.

Hence, the heat generated by the heating appliance in 10 minutes will be 69000 Joules.

Additional information :-

• Ohm's law states that - Between two circuits, the potential difference is directly proportional to the strength of current between the two circuits and inversely proportional to the resistance between them.
• Joule's law of heating effect of electric current states that the heat produced is directly proportional to the square of current strength, resistance and the time for which the electric flows in it.