Question

A heating coil of 1000 ohm resistance works in 250 v supply what is power of heater

Answer 1

Answer: 62.5 W

Explanation:

Given,

R = 1000 Ω

V = 250 V

We know that,

$P=\frac{V^{2} }{R}$

Thus,

$P= \frac{250^{2} }{1000} \\\\P=\frac{62500}{1000}\\ P=62.5 W$