Question

[p(a)}^2 + 2[p(a)]-3=0 find p(a)

Answer 1

Answer:

p(a) is -1 and 3

Step-by-step explanation:

[p(a)]² + 2[p(a)]-3=0

[p(a)]² - 3[p(a)] + [p(a)] - 3=0

p(a) [ p(a) -3] +1[ p(a) -3] = 0

([p(a)] + 1)([p(a)] - 3 = 0

(([p(a)] + 1) = 0    ; ([p(a)] - 3 = 0

([p(a)]  = -1                               ;        ([p(a)]  = 3