Question

a heavy load W is supported on a platform of area S by a applying a force F on a small piston of area S/10 the value of F for equilibrium is:

Answer 1

hence, force F for equilibrium is (W + ρgHS)/10.

explanation : using Pascal's law,

P1 = P2

⇒F1/A1 = F2/A2

see figure, F1 = load + force exerted by liquid

= W + ρgHS

A1 = S , F2 = F and A2 = S/10

so, (W + ρgHS)/S = F/(S/10)

⇒F = (W + ρgHS)/10

hence, force F for equilibrium is (W + ρgHS)/10

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